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savidgarcia303
27.08.2019 •
Mathematics
Suppose an advertising company wants to determine the current percentage of customers who read print magazines. how many customers should the company survey in order to be 98% confident that the estimated (sample) proportion is within 5 percentage points of the true population proportion of customers who read print magazines?
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Ответ:
543
Step-by-step explanation:
Given : Level of confidence = 0.98
Significance level :![\alpha=1-0.98=0.02](/tpl/images/0200/9591/b3e25.png)
By using the normal distribution table,
Critical value :![z_{\alpha/2}=2.33](/tpl/images/0200/9591/8f84a.png)
Margin of error :![E=5\%=0.05](/tpl/images/0200/9591/ef6fd.png)
The formula to find the population proportion if prior proportion of population is unknown :-
Hence, the company survey minimum sample having size =543
Ответ:
(3, 3) and (15, 15)
Step-by-step explanation:
The points equidistant from the given point and the y-axis lie on the parabola that has (3,6) as its focus and the y-axis as its directrix. The equation for that can be simplified from ...
(x -3)^2 +(y -6)^2 = x^2
-6x +9 +y^2 -12y +36 = 0 . . . . . subtract x^2, eliminate parentheses
We can find the points that lie on the line y=x (equidistant from both axes) by substituting y for x or vice versa. Then we have the quadratic ...
x^2 -18x +45 = 0 . . . . substitute x for y and collect terms
(x -3)(x -15) = 0 . . . . factor it
x = 3 or 15
So, the points of interest are (x, y) = (3, 3) and (x, y) = (15, 15).