Suppose an investment of $8200 doubles in value every 7 years. how much is the investment worth after 28 years

After 28 years, it will be $131,200

Step-by-step explanation:

It is given that the investment doubles in value every 7 years.

So, after 7 years, it will be 8200 × 2 = 16,400

After 14 years, it will be 16,400 × 2 = 32,800

After 21 years, it will be 32,800 × 2 = 65,600

After 28 years, it will be 65,600 × 2 = 131,200

Hence, the investment is $131,200 worth after 28 years.

x = 5

Step-by-step explanation:

An isosceles triangle has at least two equal sides and two equal angles.

5x - 3 = 3x + 7

Add 3 to both sides:

5x = 3x + 10

Subtract 3x from both sides.

2x = 10

Divide by 2.

x = 5

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