Mathematics: Suppose f ( a ) = 64.25 and the average rate of change of f over the interval from x = a to x = a + 199 is 0.108. What is the value of f ( a + 199 ) ? (Hint: think of the average rate of change as a constant rate of change.)

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Suppose f ( a ) = 64.25 and the average rate of

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dessssimartinez6780

21.01.2022

Mathematics

f(a+199)=85.742

Step-by-step explanation:

Here we have , Suppose f ( a ) = 64.25 and the average rate of change of f over the interval from x = a to x = a + 199 is 0.108. We need to What is the value of f ( a + 199 ) . Let's find out:

Rate of change of a function in interval [a,b] is given by:

⇒ $\frac{f(b)-f(a)}{b-a}$

Here we have the following according to info given in question ,

⇒ $\frac{f(a+199)-f(a)}{(a+199)-a} = 0.108$

⇒ $\frac{f(a+199)-64.25}{199} = 0.108$

⇒ $(199)\frac{f(a+199)-64.25}{199} = 0.108(199)$

⇒ f(a+199)-64.25 =21.492

⇒ f(a+199)=64.25 +21.492

⇒ f(a+199)=85.742

Therefore , f(a+199)=85.742 .

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Suppose f ( a ) = 64.25 and the average rate of change of f over the interval from x = a to x = a + 199 is 0.108. What is the value of f ( a + 199 ) ? (Hint: think of the average rate of change as a constant rate of change.)

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