Suppose f(x)=x^2 and g(x)=(1/3x)^2. which statement best compares the graph of g(x) with the graph of f(x)? a. the graph of g(x) is the graph of f(x) shifted 1/3 units right. b. the graph of g(x) is the graph of g(x) is the graph of f(x) horizontally stretched by a factor of 3. c. the graph of g(x) is the graph of f(x) vertically stretched by a factor of 3. d. the graph of g(x) is the graph of f(x) horizontally compressed by a factor of 3.

B. The graph of g(x) is the graph of g(x) is the graph of f(x) horizontally stretched by a factor of 3.

Step-by-step explanation:

Horizontal shifting right by c units,

Horizontally stretched by factor c.

Vertically stretched by factor c. ( where, 0< |c|<1 )

Horizontally compressed by a factor of c. ( where, |b| > 1 )

Here,

When f(x) is shifted 1/3 unit right,

Then, the transformed function is,

When f(x) is stretched horizontally by the factor of 3,

Then, the transformed function is,

When, f(x) vertically stretched by a factor of 3,

Then, the transformed function is,

When, f(x) is horizontally compressed by a factor of 3,

Then, the transformed function is,

Hence, option B is correct.

Vertically compressed by 1/9 not 3

Step-by-step explanation:

See picture attached to see comparison. The parent graph is black and the new graph is red. By adding 1/3 to the graph, the parabola becomes more compressed and wider. It is vertically compressed to become wider.

Well one way is you take $6.60 and divide it by 6 since you want to find out how much it would cost for one eraser. So after you divide $6.60 and 6 you should get 1.10. Then multiply that by three because you want to find out how much is for three and that should give you $3.30. The equation for way one is: (6.60 divide 6) times 3. Way two: There are 6 erasers right? 6 divide by three is 2 so you take 6.60 divide it by two. Way two is a little bit more complicated but u still get the same answer. Equation for way 2: 6 divide by 3= ? So then take ? times 3! Hope I helped!!