Suppose flaws (cracks, chips, specks, etc.) occur on the surface of glass with density of 3 per square meter. What is the probability of there being exactly 4 flaws on a sheet of glass of area 0.5 square meter

0.047

Step-by-step explanation:

Given that poisson distribution with mean m, for 0.5 square meter =1.5

Then the formula for finding the probability =

P[k] = (e^-m * m^k) k!

Hence we have

P[4] =[ (e^-1.5) * (1.5^4)] ÷ 4 * 3 * 2 * 1

= (0.2231301601 * 5.0625) ÷ 24

=( 1.12944375) ÷24

= 0.04706

≈ 0.047

Hence, the final answer is 0.047

the answer is b if i am correct give me briantest

step-by-step explanation: