itzdulceee
22.02.2020 •
Mathematics
Suppose S is a recursively defined set, defined by the number 1 is in S if n is in S, then so is 3n+2 - if n is in S, then so is 5n-1 if n is in S, then so is n+7 Suppose you want to prove using structural induction that all members of S have a certain property. What do you have to prove in the base step? That the numbers 5,4 and 8 have the property. That the number 1 has the property, and the numbers 5, 4 and 8. O That the numbers 5, 4 and 8 are in the set S. That the number 1 has this property.
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Ответ:
That the number 1 has this property.
Step-by-step explanation:
For base step we have to prove that number 1 has the property.
so therefore the smallest number of S is 1.
So that the number 1 has this property.
Ответ:
1/2 (12)= 6 cm
Area= πr^2
A= (3.14)(6)^2
A= (3.14)(36)
A= 113.04 cm to nearest hundredth
ANSWER: The area, rounded to the nearest hundredth, is 113.04 cm.
Hope this helps! :)