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KingSavage278
10.03.2020 •
Mathematics
Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adults were randomly selected and their preferences recorded. (Round your answers to three decimal places.)
(a) What is the probability that more than 7 preferred McDonald's?
(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?
(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?
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Ответ:
a) 0.194 = 19.4% probability that more than 7 preferred McDonald's
b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's
c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King
Step-by-step explanation:
For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
50% of all young adults prefer McDonald's to Burger King when asked to state a preference.
This means that![p = 0.5](/tpl/images/0541/4313/24486.png)
12 young adults were randomly selected
This means that![n = 12](/tpl/images/0541/4313/4d619.png)
(a) What is the probability that more than 7 preferred McDonald's?
In which
0.194 = 19.4% probability that more than 7 preferred McDonald's
(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?
0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's
(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?
Since
, this is the same as b) above.
So
0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King
Ответ:
(2, -3)
Step-by-step explanation:
Plug x = 2 into the equation y = 4x - 11
y = 4(2) - 11
y = 8 - 11
y = -3
Then, put x = 2 and y= -3 into an ordered pair.
(2, -3)