Suppose that $a$ is a positive integer for which the least common multiple of $a+1$ and $a-5$ is $10508$. What is $a^2 - 4a + 1$?

21022.

Step-by-step explanation:

Find the prime factors of 10508:

2 ) 10508

2 ) 5254

37 ) 2627

       71.

50208 = 2*2*37*71.

Now there is no integer value for a that would fit  (a+ 1)(a - 5) = 10508 .

But we could try multiplying the LCM by 2:-

= 21016  = 2*2*2*37*71.

= 2*2*37 multiplied by 2 * 71

= 148 * 142.

That looks promising!!

a - 5 = 142 and

a + 1 = 148

This gives  2a - 4 = 290

2a = 294

a = 147.

So substituting a = 147 into a^2 - 4a + 1 we get:

= 21022.

Answer & Step-by-step explanation:

The problem tells us that ΔABC ≅ ΔDEF. Since we know that this is true, then we also know that ∠A ≅ ∠D, ∠B ≅ ∠E, and ∠C ≅ ∠F.

So, since we are looking for the measurement of ∠F, then all we have to do is know the measurements of ∠C because they are congruent angles.

So, the measurement of ∠F is 63°