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kendrawalraven
31.12.2019 •
Mathematics
Suppose that a value of a measurement is distributed with mean 200 and standard deviation 5. suppose the distribution is normally distributed as well
calculate the probability that a single measurement exceeds 201.
b) calculate the probability that an average of 100 measurements exceeds 201
c) can part (a) be answered if we drop the assumption that the distribution is normal?
d) can part (b) be answered if we drop the assumption that the distribution is normal?
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Ответ:
Step-by-step explanation:
Given that a value of a measurement is distributed with mean 200 and standard deviation 5.
Let X be the value of measurement
X is N(200,5)
a) The probability that a single measurement exceeds 201.
=![P(Z0.2)\\= 0.5-0.0793\\=0.4207](/tpl/images/0437/6958/3e7ef.png)
b)The probability that an average of 100 measurements exceeds 201
=![P(Z\frac{1}{\frac{5}{\sqrt{100} } } \\=P(Z2)\\=0.0228](/tpl/images/0437/6958/bb09c.png)
c) Can part (a) be answered if we drop the assumption that the distribution is normal?
No, we cannot. For a single item only if normal distribution is given we can do this.
d) Can part (b) be answered if we drop the assumption that the distribution is normal?
Yes, because when sample sizes are large, the mean follows normal irrespective of original distribution
Ответ:
.
We know the Area (6,450.35 square yards), and the length (90.85 yards). Substituting these in the formula we have:
.
Thus, (yards).
71 yards