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davidaagurto
26.03.2020 •
Mathematics
Suppose that birth weights are normally distributed with a mean of 3466 grams and a standard deviation of 546 grams. Babies above the 95th percentile have a condition called macrosomia (also known as "big baby syndrome"). What birth weight marks the 95th percentile?
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Ответ:
A birth weight of 4364.17 grams marks the 95th percentile.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What birth weight marks the 95th percentile?
This is X when Z has a pvalue of 0.95. So it is X when Z = 1.645.
A birth weight of 4364.17 grams marks the 95th percentile.
Ответ:
angles x and y are complimentary angles, hat means that their angles added together have a total of 90 degrees.