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smariedegray
04.07.2019 •
Mathematics
Suppose that receiving stations x, y, and z are located on a coordinate plane at the points (3,3), (-13, −5), and (-5,3), respectively. the epicenter of an earthquake is determined to be 5 units from x, 13 units from y, and 5 units from z. where on the coordinate plane is the epicenter located?
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Ответ:
The epicenter lies on a circle with radius=5 from X(3,3). Therefore
(x-3)² + (y-3)² = 25 (1)
Y(-13,-5) has the epicenter on a circle with radius=13, therefore
(x+13)² + (y+5)² = 169 (2)
Z (-5,3) has the epicenter on a circle with radius = 5, therefore
(x+5)² + (y-3)² = 25 (3)
Subtract (1) from (3).
(x+5)² - (x-3)² = 0
x² + 10x + 25 - x² + 6x - 9 = 0
16x = -16
x = -1
From (1), obtain
16 + (y-3)² = 25
(y-3)² = 9
y = 0 or y = 6
Check answers with (2).
When x=-1, y=0. obtain
(x+13)² + (y+5)² = 169 (Correct, Accept)
When x=-1, y=6, obtain
(x+13)² + (y+5)² = 265 (Incorrect, Reject)
The epicenter is at (-1,0).
Graphical solution (see the figure below).
From X (3,3), draw a circle with radius =5.
From Z (-5, 3), draw a circle with radius = 5.
The only point where all three circles intersect is (-1, 0) approximately.
The epicenter is at (-1,0)
Ответ:
x = 60
y = 13.9
z = 16
Step-by-step explanation: