Suppose that salaries for recent graduates of one universityhas a means of 25,100 with a standard deviation of 1400. Using chebyshevs theorem, what is the minimum percentage of recent graduates who have salaries between 22,300 and 27,900

The correct option is a. 43°

Step-by-step explanation:

In triangle LMN,

NP is perpendicular bisector, i.e. LP = PM and m∠NPM = m∠NPL = 90°,

Also, LN = NM,

Since, the sum of all interior angles of a triangle is 180°,

∴ m∠NPM + m∠NMP + m∠MNP = 180°

We have,  

m∠NMP = 47° ( given ),

90° + 47° + m∠MNP = 180°

137° + m∠MNP = 180°

m∠MNP = 180° - 137° = 43°,

Now, in triangles NLP and NMP,

LP = PM,

LN = NM,

PN = PN,

By SSS postulate of congruence,

Δ NLP ≅ Δ NMP

By CPCTC,

m∠PNL = m∠MNP

⇒ m∠PNL = 43°

Hence, OPTION a. is correct.