lukelara
02.03.2020 •
Mathematics
Suppose that we have a fuse box containing 20 fuses, of which 5 are defective. If 2 fuses are selected at random and removed from the box in succession without replacing the first, what is the probability that both fuses are defective?
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Ответ:
0.0526 (3 sf)
Step-by-step explanation:
(5/20)×(4/19)
= 0.0526315789
= 0.0526 (3 sf)
Ответ: