electronia
12.01.2020 •
Mathematics
Suppose that you lose $10 if the dice sum to 7 and win $11 if the dice sum to 3 or 2. how much should you win or lose if any other number turns up in order for the game to be fair?
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Ответ:
E[X] = ∑ P(x)*x.
We assume we don't need to pay to play the game.
When throwing two dice, the probabilitiy of throwing a 7 is
P(7)=6/36 (pays x=$10)
(6 because there are six possible outcomes, {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)}.
Similarly,
P(2)=1/36 (pays x=$11)
P(3)=2/36 (pays x=$11)
We assume the payout is x=k for the other outcomes, with total probability of (36-6-1-2)/36=27/36
Therefore the expected gain is
E[X]=P(7)*10+P(2)*11+P(3)*11+P(others)*k
For the game to be fair, we have E[X]=0, or
P(7)*10+P(2)*11+P(3)*11+P(others)*k=0
=>
k=-(P(7)*10+P(2)*11+P(3)*11)/P(others)
=-(6*10+2*11+3*11)/(27)
= -115/27
=-4.26 approximately.
Ответ:
it is c
Step-by-step explanation: