Mathematics: Suppose the average math SAT score for students enrolled at local community college is 490.4 with a standard deviation of 63.7. A random sample of 49 students has been selected. The standard error of the mean for this sample is . 10.6 9.1 63.7 28.4 The standard deviation of X^bar (or the standard error of the sample mean) is calculated as the positive squareroot of the variance. It is computed as se(X^bar) = sigma/Squareroot n.

Suppose the average math SAT score for students

g0606997

21.01.2022

Option B) 9.1

Step-by-step explanation:

We are given the following in the question:

Average score = 490.4

Standard deviation = 63.7

Sample size, n = 49

Formula:

$=\dfrac{\sigma}{\sqrt{n}}$

Putting values, we get,

Standard error =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{63.7}{\sqrt{49}} = 9.1$

Thus, the correct answer is

Option B) 9.1

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kay2420

14.06.2020

Because D is the midpoint of AB, AD = 1/2 x AB.

AD = 1/2 x 15 = 7.5

7.5

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