Mathematics: Suppose the difference between actual and predicted weekly sales of a company follows a uniform distribution between -$4000 and $4000. Determine the probability that the actual sale is within $1500 of the predicted sale (which means P(-1500

Suppose the difference between actual and predicted

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girlygirl2007

06.02.2022

0.375

Step-by-step explanation:

Given: The difference between actual and predicted weekly sales of a company follows a uniform distribution between -$4000 and $4000.

Probability density function: $f(x)=\dfrac{1}{b-a}=\dfrac{1}{4000-(-4000)}=\dfrac{1}{8000}$

The probability that the actual sale is within $1500 of the predicted sale = $\int^{1500}_{-1500}f(x)dx=\int^{1500}_{-1500}\dfrac{1}{8000}dx=\dfrac{1}{8000}[x]^{1500}_{-1500}\\\\= \dfrac{1}{8000}(1500-(-1500))\\\\= \dfrac{1}{8000}(3000)=0.375$

Hence, Required probability =0.375

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Suppose the difference between actual and predicted weekly sales of a company follows a uniform distribution between -$4000 and $4000. Determine the probability that the actual sale is within $1500 of the predicted sale (which means P(-1500

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