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michellemonroe012305
24.05.2020 •
Mathematics
Suppose there are two types of tickets to a show advance and same day. Advance tickets cost $25 and same dayt costs $15 for one performamnce there were 50 tickets sold in all the total amount paid for them was $1050 how many tickets of each type were sold
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Ответ:
Advanced tickets=30 Day =20
Step-by-step explanation:
Put them into equations:
x=advanced
y=day
x+y=50
25x+15y=1050
to make it simpler re-arrange x+y=50
x=50-y
Then substitute into 25x+15y=1050
25(50-y)+15y=1050
Expand
1250-25y+15y=1050
Rearrange
25y-15y=1250-1050
Work the above out
10y=200
y=20
and then
20+x=50
meaning
x=30
showing Advanced tickets=30 Day =20
Ответ:
x=1.375
step-by-step explanation:
7-4x'2= 18
4x'2=11
x'2=11/4
x=1.375