Mathematics: Suppose x has a normal distribution with mean μ = 45 and standard deviation σ = 9. describe the distribution of x values for sample size n = 4. (round σx to two decimal places.) μx = σx =

Suppose x has a normal distribution with mean μ =

Ответ:

21vdawson

15.03.2022

The standard deviation of a particular sample is equal to the standard deviation divided by the square root of the sample size. That is, $\sigma_x=\frac{\sigma}{\sqrt n}$
The mean of a particular sample is equal to the mean of the set the sample was taken from. That is,
$\mu_x=\mu$
$\text{In your case, }\sigma_x=\frac{9}{\sqrt4}=\frac92\text{ and }\mu_x=45.$