Suppose you have an unfair coin that comes up heads 60% of the time and tails 40% of the time. you play a game where you flip the coin a single time and you lose $2 if you get heads and you win $3 if you get tails. what is the expected value of your outcome?

The expected value is that you lose 2$ because you come up with heads 60% of the time, which is the most likely outcome, and if you come up with heads then you lose 2$.

Question 1

f(x) represents the distance of the cannon from the ground

Question 2

When f(x) = 0, there will two values of 'x'. The point on the positive x-axis where the graph crosses represent the point where the cannon hits the ground.

Question 3

Yes, it would. By knowing the spot where the cannon will hit the ground, we can set the net at the spot.

Question 4

f(x) = 0
-0.05 (x² - 26x -120) = 0
x² - 26x - 120 = 0

Question 5

Please refer to the table attached below

Question 6

The value of p and q that gives the correct factors are -30 and 4 since it gives p+q = -26

Question 7

Factorising the equation completely

-0.05 (x² - 26x - 120) = 0
-0.05 (x+4) (x-30) = 0 
(x+4) (x-30) = 0

Question 8
 
Solving the equation

x+4 = 0 and x-30=0
x=-4 and x=30 

Question 9 

The roots of the equation is x = -4 and x = 30

Question 10

Please refer to the third graph

Question 11

Yes

Question 12

The negative zero means the initial distance of the cannon, where it was fired from

Question 13

The distance between x = -4 and x = 30 is 34 units. If the cannon was fired from the point when x = -4, the cannon will hit the ground again 34 units from the point it was fired from. If Nik put a net 30 units from the firing point, the cannon will fly pass it.