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Luzperez09
29.07.2019 •
Mathematics
Suzy likes to mix and match her 3 necklaces, 2 bracelets, and 6 hats. the colors are listed in the table. on monday, she randomly picks a bracelet, a necklace, and a hat. what is the probability of suzy choosing a red bracelet and silver hat? necklace colors: red ,green ,gold bracelet colors: red and black hat colors: silver, yellow, green, gold, black, and white a. one-half b. one-fourth c. start fraction 1 over 6 end fraction d. start fraction 1 over 12 end fraction
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Ответ:
We have:
3 Necklaces (red, green, and gold)
2 Bracelets (red and black)
6 hats (silver, yellow, green, gold, black, and white)
The number total of combinations is:
C=3x2x6→C=36 possible combinations
What is the probability of Suzy choosing a red bracelet and silver hat?
Possible combinations with a red bracelet and silver hat:
C1=1 (red bracelet) x 1 (silver hat) x 3 (necklaces: red, green, and gold)
C1=3 possible combinations with a red bracelet and silver hat
Probability of Suzy choosing a red bracelet and silver hat: P=C1/C
P=3/36
Simplifying the fraction dividing the numerator and the denominator by 3:
P=(3/3) / (36/3)
P=1/12
The probability of Suzy choosing a red bracelet and silver hat is 1/12
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