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Dogtes9667
18.01.2021 •
Mathematics
Sweety’s mother is 12 years more than twice Sweety’s age. After 8 years, she will be 20 years less than three times Sweety’s age. Find Sweety’s age and Sweety’s mother’s age?
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Ответ:
Sweety's age = 16 years and Sweety’s mother’s age = 44 years
Step-by-step explanation:
Let Sweety's age is x.
Sweety’s mother age = 12+2x
After 8 years,
Sweety's age = x+8
Sweety’s mother age = 12+2x+8
Since Mother's age will be 20 years less than three times my age.
2x+20 = 3(x+8)-20
2x+20=3x+24-20
2x+20=3x+4
Taking like terms together,
20-4=3x-2x
x = 16
Sweety's age = 16 years
Sweety’s mother’s age = 12+2x
= 12+2(16)
= 12 + 32
= 44 years
Hence, Sweety’s age and Sweety’s mother’s age is 16 years and 44 years respectively.
Ответ:
D
Step-by-step explanation:
G+110=180 as they are pair of angles on traversal line.