Mathematics: System of equation by elimination 4x-6y=10 and 3x+6y=4

System of equation by elimination 4x-6y=10 and 3x+6y=4

Ответ:

lee2125

04.01.2022

Solving:

$\left \{ {{4x-6y=10\:(I)} \atop {3x+6y=4\:(II)}} \right.$

$\left \{ {{4x-\diagup\!\!\!\!\!6y=10} \atop {3x+\diagup\!\!\!\!\!6y=4}} \right.$

$\left \{ {{4x=10} \atop {3x=4}} \right.$
----------------------
7x = 14

$x = \frac{14}{7}$
$\boxed{\boxed{x = 2}}\end{array}}\qquad\quad\checkmark$

Now replace the found value of "x" in equation (II) to find the value of "y"

$3x+6y=4\:(II)$
3*(2) + 6y = 4