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lclaudettecarte3550
15.12.2019 •
Mathematics
![2(x - 8) + 4x = 6(x - 2) - 4](/tex.php?f=2(x - 8) + 4x = 6(x - 2) - 4)
how do i solve this one?
Solved
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Ответ:
In this question, you're solving for x.
Solve for x:
2(x - 8) + 4x = 6(x - 2) - 4
Distribute the 2 to the variables inside the parenthesis.
2x - 16 + 4x = 6(x - 2) - 4
Distribute the 6 to the variables inside the parenthesis.
2x - 16 + 4x = 6x - 12 - 4
6x - 16 = 6x - 12 - 4
6x - 16 = 6x - 16
Subtract 6x from both sides
-16 = -16
Add 16 to both sides
0 = 0
All real numbers and solutions
Ответ:
2x+4x=6x4-4
6x=6x
X=0
Ответ:
(2.06x102x1.88 x 10-1) <7.69x 10
2.3x10-5
Step-by-step explanation: