Mathematics: [tex]f= rac{9}{5}c + 32[/tex]solve for c.

Step-by-step explanation:Real solutions (): However, recall that . Therefore:.Thus, for :.Therefore, the real and nonreal solutions of are ....

[tex]f= \frac{9}{5}c + 32[/tex]solve for c. - id95321629621, uniqueray33

oliviaprejean18

26.01.2023

$x=-2, \:1+\sqrt{3}i,\: 1-\sqrt{3} i$

Step-by-step explanation:

$x^3+8=0,\\x^3=-8,\\\mathrm{For\:}x\in \mathrm{R}, x=-2$

Real solutions ( $x \in \mathrm{R}$ ): x=-2

However, recall that $(\frac{-1\pm\sqrt{3}i}{2})^3=1$ .

Therefore:

$\frac{-1\pm\sqrt{3}i}{2}\cdot -2=-2$ .

Thus, for $x^3=-8,\: x\notin \mathrm{R}$ :

$x=1\pm\sqrt{3}i$ .

Therefore, the real and nonreal solutions of x^3+8=0 are $\fbox{$-2, \:1+\sqrt{3}i,\: 1-\sqrt{3}i$}$ .

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