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Riplilpeep
26.12.2019 •
Mathematics
The age of mary, jo, and larry have a sum of 120. mary's age is three times jo's age, and larry's age is 5 less than jo's age. find the age's of mary, jo, and larry. and fill in these blanks. if mary's age is 75 then jo's and larry's age
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Ответ:
Let J = Jo's age
Let L = Larry's age.
The sum of their ages is 120. Therefore
M + J + L = 120 (1)
Mary's age is three times Jo's age. Therefore
M = 3J (2)
Larry's age is 5 less than Jo's age. Therefore
L = J - 5 (3)
Substitute (2) and (3) into (1).
3J + J + (J-5) = 120
3J + J + J - 5 = 120
5J - 5 = 120
5J = 120 + 5 = 125
J = 125/5 = 25
Therefore
J = 25, M = 3J = 75, L = J - 5 = 20
Mary's age = 75; Jo's age = 25; Larry's age = 20
If Mary's age is 75, then Jo's age is 25, and Larry's age is 20.
Ответ:
Mary is 3x, Larry is x-5
So x + 3x + (x-5) = 120
x = 25
So Jo is 25, Mary is 25*3 = 75, Larry is 25-5 = 20
Ответ: