GOOBER3838
14.01.2020 •
Mathematics
The angle of elevation of the top of a vertical pole as seen from a point 10 meters away from the pole is double its angle of elevation as seen from a point 70 meters from the pole. find the height of the pole above the level of the observer's eyes.
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Ответ:
59.2 m
Step-by-step explanation:
The tangent of the angle of elevation will be the ratio of pole height to distance from the pole:
tan(2α) = h/10
tan(α) = h/70
The double-angle formula for tangents tells us ...
tan(2α) = 2tan(α)/(1 -tan(α)²)
Multiplying by the denominator and substituting from above, we get ...
(1 -(h/70)²)(h/10) = 2(h/70)
7(1 -(h/70)²) = 2 . . . . . . . . multiply by 70/h
1 - 2/7 = (h/70)² . . . . . . . . divide by 7, subtract 2/7-(h/70)²; next: square root
h = 70√(5/7) ≈ 59.2 . . . . meters
The height of the top of the pole is about 59.2 meters above the observer.
Ответ:
Which of the following graphs show a proportional relationship?
Choose all answers that apply:
The answer is A.