recon12759
29.01.2020 •
Mathematics
The area of a rectangle is 52 in². the length of the rectangle is 9 in. longer than the width.
what is the width of the rectangle?
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Ответ:
A = 52
L = W + 9
52 = W(W + 9)
52 = W^2 + 9W
W^2 + 9W - 52 = 0
(W - 4)(W +13) = 0
W - 4 = 0
W = 4 <=== its this one...the width is 4 in
W + 13 = 0
W = -13...extraneous solution
Ответ:
I had taken a test, but I don't know if you guys have the same as me but your answer will be 4in.
Ответ:
If you start at (-3,1) and end up at (0,3), you will have increased x by 3 and y by 2. Thus, the slope of this line is m = rise / run = 3 / 2.
Using the point-slope form of the equation of a straight line, we get:
y - 1 = (3/2)(x+3).
This could be rewritten in other forms:
y = 1 + (3/2)x + 9/2, or y = 2/2 + (3/2)x + 9/2, or y = (3/2)x + 11/2.