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warnene17
25.11.2019 •
Mathematics
The area of a rectangular room is 750 square feet. the width of the room is 5 feet less than the length of the room.
which equations can be used to solve for y, the length of the room? check all that apply.
y(y + 5) = 750
y2 – 5y = 750
750 – y(y – 5) = 0
y(y – 5) + 750 = 0
(y + 25)(y – 30) = 0
Solved
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Ответ:
Option B , C and E are correct
(y+25)(y-30)=0
Step-by-step explanation:
Given : Area of rectangular room is 750 square feet.
Width of the room is 5 feet less than the length of the room.
Let y be the length of the room
then,
As per the given condition
width of the room is: y-5
Area of rectangle is multiply the length by its width.
Area of rectangle =![length \times width](/tpl/images/0390/5239/637fd.png)
Substitute the given values in above formula we get;
or we can write this as;
750 -y(y-5)=0
[1] ⇒
or
(y+25)(y-30)=0
Therefore, the equation which can be used to solve for y are;
Ответ:
A:False
B:True
C:True
D:False
E:True
Ответ:
P=12,000
R=9%
T=4
SI= prt/100
=12,000*9*4/100
=432,000/100
=4,320