The area of a square poster is 59 in.² find the length of one side of the posterior to the nearest 10th of an inch

area of a square = S^2

to find length of side take square toot of area

sqrt(59) = 7.68114

to nearest tenth = 7.7 inches

For problem #4 the answer is 100°. The triangle are congruent meaning the angles that are given both of the triangle have to have the same angles.

The triangle sum theorem is all triangles have a 180° . All the 3 angles = 180.

They gave you two angles of the triangle. So add the two angles and find the difference of 180.

50+30=80

180-80=100°

#5 set those 2 angles equal. Because the A corresponds to Q. Solve for X and plug in your x value