vanvalenpeyt
30.09.2019 •
Mathematics
The average value of sqrt 3x on the closed interval [0,9] is?
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Ответ:
fAV = ∫ √(3x) dx/(9 - 0) = ∫ (3x)^(1/2)
then simplify the equation
dx/9 = 31.17691497../9 ≈
Then the answer would be.
3.464
I hope I helped you with your problem. Have a nice day
Ответ:
the correct answer is $30
Step-by-step explanation: