The base of a regular pyramid is a hexagon. what is the area of the base of the pyramid? (express your answer in radical form)

Since angle c is 30° the side lengths of the hexagon are 14 cm as well, which is always true of hexagons because if you divide the hexagon into six triangle they are all equilateral triangles...the area of any regular polygon can be expressed as:

A(n,s)=ns^2/(4tan(180/n)), n=number of sides, s=side length...in this case:

A(6,14)≈509.22 cm^2

The expression you would use is the slope formula which is
m= (Y2-Y1)/(X2-X1)
Let me know if you need further help! :)