The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.37degreesf and a standard deviation of 0.49degreesf. using the empirical rule, find each approximate percentage below. a. what is the approximate percentage of healthy adults with body temperatures within 2 standard deviations of the mean, or between 97.39degreesf and 99.35degreesf? b. what is the approximate percentage of healthy adults with body temperatures between 97.88degreesf and 98.86degreesf?

The approximate percentage of healthy adults with body temperatures within 2 standard deviations of the mean, or between 97.39°F to 99.35°F  is 95%.

The approximate percentage of healthy adults with body temperatures between 97.88°F to 98.86°F is 68%.

Step-by-step explanation:

Mean :

Standard deviation :

Empirical rule :

1 ) 68% of the data lies within 1 standard deviation of mean

i.e. 68% of data lies between: to

So, On the given data

to

to

So, 68% of data lies between 97.88°F to 98.86°F.

2) 95% of the data lies within 2 standard deviation of mean

i.e. 95% of data lies between: to

So, On the given data

to

to

So, 95% of data lies between 97.39°F to 99.35°F .

3) 99.7% of the data lies within 3 standard deviation of mean

i.e. 99.7% of data lies between: to

So, On the given data

to

to

So, 99.7%  of data lies between 96.9°F to 99.84°F .

The approximate percentage of healthy adults with body temperatures within 2 standard deviations of the mean, or between 97.39°F to 99.35°F  is 95%.

The approximate percentage of healthy adults with body temperatures between 97.88°F to 98.86°F is 68%.

The approximate percentage of healthy adults with body temperatures within 2 standard deviations of the mean, or between 97.39°F to 99.35°F is 95%.

The approximate percentage of healthy adults with body temperatures between 97.88°F to 98.86°F is 68%.

Given that,

The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.37degreesF,

Standard deviation of 0.49degreesF.

We have to find,

Using the empirical rule, find each approximate percentage below. the approximate percentage of healthy adults with body.

According to the question,

Mean :

Standard deviation :

By Empirical rule :

i.e. 68% of data lies between: to  

So, in the given data,

= 98.37 - 0.49 to 98.37 + 0.49  

= 97.88 to 98.86

So, 68% of data lies between 97.88°F to 98.86°F.

i.e. 95% of data lies between:  to

So, in the given data,

= 98.37 - 2(0.49)  to 98.37 + 2(0.49)

= 97.39 to 99.35

So, 95% of data lies between 97.39°F to 99.35°F .

i.e. 99.7% of data lies between:  

So, in the given data,

to

= 98.37 - 3(0.49) to 98.37 + 3(0.49)

So, 99.7%  of data lies between 96.9°F to 99.84°F .

The approximate percentage of healthy adults with body temperatures within 2 standard deviations of the mean, or between 97.39°F to 99.35°F is 95%.

The approximate percentage of healthy adults with body temperatures between 97.88°F to 98.86°F is 68%.

For more information about Standard deviation click the link given below.

link

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Step-by-step explanation:

Cleo buys x packs of markers, y wide-ruled notebooks, and z college-ruled notebooks.

All spiral-bound notebooks, whether wide-ruled or college-ruled, sell for $1.20 each. This gives expressions : 1.20y and 1.20z

A store sells four-packs of permanent markers in assorted colors for $3.19 per pack. Cleo buys x packs of markers so expression becomes :

(3.19 per pack)

As Cleo buys x packs of markers, y wide-ruled notebooks, and z college-ruled notebooks.

The combined expression becomes:

The store charges a 6% sales tax on Cleo’s total bill. So, expression becomes:

() *0.06