The boys basketall team averages 52 points per game with a standard deviation of 7.0 points. What is the probability that the boys will score between -1.2 and 2.0 standard deviations of their average?

0.6832

Step-by-step explanation:

Given :

Mean, m = 52

Standard deviation, s = 7

-1.2 standard deviation of average = 57 - 1.2(7) = 57 - 8.4 = 48.6

2 standard deviations of average = 57 + 2(7) = 57 + 14 = 71

Zscore = (48.6 - 52) / 7 = - 0.486

Zscore = (71 - 52) / 7 = 2.714

P < -0.486) = 0.31348

P < 2.714 = 0.99668

P < 2.714 - P < -0.486 = (0.99668 - 0.31348) = 0.6832