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lydia1melton
04.07.2019 •
Mathematics
The center of a circle is located at (6, −1) . the radius of the circle is 4.
what is the equation of the circle in general form?
x2+y2−12x+2y+21=0
x2+y2−12x+2y+33=0
x2+y2+12x−2y+21=0
x2+y2+12x−2y+33=0
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Ответ:
Ответ:
ANSWER
Option A
EXPLANATION
When a circle has it's center at (h,k) and and radius r units, then its equation in standard form is
The given circle has its center at (6,-1) and its radius is r=4 units.
We plug in these values to get
We now expand to obtain
This is the equation in general form of the circle.
Ответ: