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LoneWolves
31.07.2020 •
Mathematics
The circle below has center C. Suppose angle EDF = 84º and DF is tangent to the circle at D.
Find the following. Type your numerical answers (without units) in each blank.
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Ответ:
Step-by-step explanation:
In the given , we have a circle centered at C , ED is a chord and DF is a tangent touching circle at D, ∠EDF = 84°.
Also, CE = CD = radius
⇒ ∠CED = ∠CDE ---(i) [angles opposite to equal sides of triangle are equal]
Since radius makes a right angle with tangent.
So, ∠CDF = 90°
⇒ ∠CDE =∠CDF - ∠EDF
⇒ ∠CDE= 90° - 84°
⇒ ∠CDE = 6°
From (i) ∠CED =∠CDE = 6°
In ΔCDE
⇒∠CED + ∠CDE + ∠ECD = 180°
⇒ 6°+6°+ ∠ECD = 180°
⇒ 12°+ ∠ECD = 180°
⇒∠ECD = 180° - 12°
⇒∠ECD = 168°
Since , Angle measure of the central angle is equal to the measure of the intercepted arc.
Therefore m∠ECD =![m\overbrace{ED}](/tpl/images/0715/9792/1d475.png)
⇒
= 168°
Hence,
= 168° and ∠ECD = 168°
Ответ:
The points create a quadrilateral shape
Step-by-step explanation:
By the way you can to to desmos.com or look up desmos coordinate plane to put in points and see what shape they would make on a coordinate plane.