Mathematics: the circle below is centered at the point (8,4) and has a radius of length 4. what is its equation? o a. (x-4)2 + (y + 8)2 = 4 o b. (x-8)2 + (y-4)2 = 16 o c. (x-4)2 + (7-8)2 = 10 42 o d. (x+8)2 + (9-4)2 = 16 submit

the circle below is centered at the point (8,4)

Ответ:

Toni1816

08.01.2022

$\textbf{The equation of the circle is: $ {(x-8)}^2 + {(y-4)}^2 = 16 $.}\\$

Step-by-step explanation:

$\textup{The equation of a circle is given by:}\\$$c = \sqrt{{(x-h)}^2 + {(y-k)}^2} = r^2$$\\\textit{where $(h,k)$ represents the centre of the circle and $r$ the radius.}\\\textup{Given the centre of the circle is $(8,4)$ and radius is $4$.}$ \therefore $ We have $$c = \sqrt{{(x-8)}^2 + {(y-4)}^2} = 4^2$$$\implies {(x-8)}^2 + {(y-4)}^2 = 16$$

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Ответ:

nehemiahj8

12.06.2022

Mathematics

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Step-by-step explanation:

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the circle below is centered at the point (8,4) and has a radius of length 4.
what is its equation?
o a. (x-4)2 + (y + 8)2 = 4
o b. (x-8)2 + (y-4)2 =
16
o c. (x-4)2 + (7-8)2 =
10
42
o d. (x+8)2 + (9-4)2 =
16
submit

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