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MayFlowers
09.10.2019 •
Mathematics
The coordinates of the vertices of a triangle are (−4,2), (5−1), and (−3,−2).
what is the perimeter of the triangle, to the nearest tenth of a unit?
a: 13.1 units
b: 19.6 units
c: 21.7 units
d: 38.2 units
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Ответ:
d = √[(x2 - x1)^2 + (y2 - y1)^2]
1) d = √[(5+4)^2 + (2+1)^2] = √[81 + 9] = √90
2) d = √[(1)^2 + 4^2] = √[1 + 16] = √17
3) d = √[8^2 + 1^2] = √[64 + 1] = √65
Perimeter = √90 + √17 + √65 = 21.7
Ответ:
a elvauvate
1) 13
2) 1/27
b work out
ans = 4
c sorry dont know
Step-by-step explanation: