Mathematics: The coordinates of the vertices of △pqr are p(2,−1), q(4,2), and r(6,0). identify the perimeter of △pqr. round each side length to the nearest tenth before adding.

The coordinates of the vertices of △pqr are p(2,−1),

marisol56

12.03.2022

The perimeter of △pqr is 10.5

Explanation

The coordinates of the vertices of △pqr are p(2,−1), q(4,2), and r(6,0)

First we need to find the length of each side of the triangle using distance formula between two points.

The length of pq $=\sqrt{(2-4)^2+(-1-2)^2}=\sqrt{(-2)^2+(-3)^2}=\sqrt{4+9}=\sqrt{13}=3.6$ ,

the length of qr $=\sqrt{(4-6)^2+(2-0)^2}=\sqrt{4+4}=\sqrt{8}=2.8$

and the length of pr $=\sqrt{(2-6)^2+(-1-0)^2}=\sqrt{16+1}=\sqrt{17}=4.1$

As the perimeter means the sum of all sides, so the perimeter =3.6+2.8+4.1=10.5

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claytonashley30

27.10.2021

f(x)=x^4-58x^2+1212x-10080

Step-by-step explanation:

The given polynomial has zeros:

x=8,x=-14,x=3+9i

By the complex conjugate property, x=3-9i is also a zero of the polynomial.

The polynomial can be written in factored form as:

f(x)=(x-8)(x+14)(x-(3+9i))(x-(3-9i))

We expand to get:

f(x)=(x^2+6x-112)(x^2-6x+90)

We expand further to get:

f(x)=x^4-58x^2+1212x-10080

The last choice is correct.

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