Mathematics: The current in an electrical conductor varies inversely as the resistance of the conductor. what is the current when the resistance is 42 ohms, if the current is 4 amperes when the resistance is 168 ohms?

The current in an electrical conductor varies inversely

Ответ:

jess4791

14.03.2022

The inverse relationship between the current and the resistance can be expressed as follows, where the product of the current and the resistance is constant:

(current_1)(resistance_1)=(current_2)(resistance_2)

(current_1)(resistance_1)=(current_2)(resistance_2)

Once you establish this relationship, just plug in the numbers given:

$(4 \text{ amperes})(168 \text{ ohms})=(x \text{ amperes})(42 \text{ ohms}) \newline \newline 672=42x \newline \newline x=16 \text{ amperes}$

Another way to think of this is that, in an inverse relationship, if one quantity is multiplied by a certain factor, the other quantity must be divided by that same factor, and vice versa. Since the ohms are being divided by 4:

$\frac{168}{4}=42$

Then the amperes must be multiplied by 4:

4*4=16

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Ответ:

mckennacwilliams

19.11.2022

Mathematics

I don’t know the answer I just need some points to ask more questions

Step-by-step explanation:

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The current in an electrical conductor varies inversely as the resistance of the conductor. what is the current when the resistance is 42 ohms, if the current is 4 amperes when the resistance is 168 ohms?

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