The curve with equation y = x^2 + ax + 3 has a stationary point when x = 4. Find a.

Step-by-step explanation:

y=x^2+ax+3

y=(4)^2+a(4)+3

y=16+4a+3

y=19+4a

y-19=4a

y-19/4=a

a=y-4.75

Answer with explanation:

Equation of Parabola that opens Downward having vertex at (0,4) is given by:

It is also given that,  vertex of a second parabola is at (0, –4).

Also, it is given that Parabola Intersect at two points.

 So, the parabola must open upward to intersect at two points.

Equation of Parabola having vertex (0,-4) ,is given by:

It is not necessary that , point of intersection is on the x axis, the two parabolas can intersect anywhere.

Option B: The second parabola opens upward