The data show the chest size and weight of several bears. find the regression equation, letting the first variable be the independent (x) variable. then find the best predicted weight of a bear with a chest size of 63 inches. use a significance level of 0.05.

Solved

Show answers

Ответ:

teacherpreacher

22.04.2023

Mathematics

$\begin{bmatrix}\mathrm{Solution:}\:&\:\frac{9-\sqrt{149}}{6}$

Step-by-step explanation:

$\frac{5}{3\left(6x+3\right)}$

$\frac{-36x^2+108x+68}{6x+3}$

$\frac{-4\left(x-\frac{9+\sqrt{149}}{6}\right)\left(x-\frac{9-\sqrt{149}}{6}\right)}{3\left(2x+1\right)}$

$\frac{\left(-4\left(x-\frac{9+\sqrt{149}}{6}\right)\left(x-\frac{9-\sqrt{149}}{6}\right)\right)\left(-1\right)}{3\left(2x+1\right)}0\cdot \left(-1\right)$

$\frac{4\left(x-\frac{9+\sqrt{149}}{6}\right)\left(x-\frac{9-\sqrt{149}}{6}\right)}{3\left(2x+1\right)}0$

$\frac{3\cdot \:4\left(x-\frac{9+\sqrt{149}}{6}\right)\left(x-\frac{9-\sqrt{149}}{6}\right)}{3\left(2x+1\right)}0\cdot \:3$

$\frac{4\left(x-\frac{9+\sqrt{149}}{6}\right)\left(x-\frac{9-\sqrt{149}}{6}\right)}{2x+1}0$

$\frac{\frac{4\left(x-\frac{9+\sqrt{149}}{6}\right)\left(x-\frac{9-\sqrt{149}}{6}\right)}{2x+1}}{4}\frac{0}{4}$

$\frac{9-\sqrt{149}}{6}$

0,0(0 оценок)

Ask your question to the AI advisor

Ai-bot is an expert in any field and is the perfect companion for reliable and useful answers and advice on a variety of topics, including science, history, technology, art, sports, health, culture and more.

Ask your question

More tips

Answers on questions: Mathematics

Ask an AI advisor a question

I want advice