the density of salt is 80 pounds per cubic foot what is the approximate density of salt per cubic meter

Density = 1,282.26 kg/m^3

Step-by-step explanation:

Density =  80 lb/ft^3

We know that:

1lb = 0.4536 kg.

1ft^3 = 0.0283 m^3

then we can write:

1 = (0.4536kg)/(0.0283 m^3)*(1ft^3/lb)

we can multiply our equation by this, and it wont be affected, then we have:

Density = 80 lb/ft^3 = 80 lb/ft^3 (0.4536kg)/(0.0283 m^3)*(1ft^3/lb)

Density = 1,282.26 kg/m^3

Density = 1,282.26 kg/m^3

Step-by-step explanation:

Density =  80 lb/ft^3

We know that:

1lb = 0.4536 kg.

1ft^3 = 0.0283 m^3

then we can write:

1 = (0.4536kg)/(0.0283 m^3)*(1ft^3/lb)

we can multiply our equation by this, and it wont be affected, then we have:

Density = 80 lb/ft^3 = 80 lb/ft^3 (0.4536kg)/(0.0283 m^3)*(1ft^3/lb)

Density = 1,282.26 kg/m^3

Step-by-step explanation:

Solution:

The two equation given which are in two variables are

1. y = x²-2 x -1 9

2. y + 4 x=5

Writing equation 2 as→y = 5 -4 x

Substituting the value of y in equation 1

⇒ 5 - 4 x = x² - 2 x - 19

⇒x² - 2 x + 4 x -19 -5=0

⇒ x² + 2 x -24=0

⇒x² + 6 x - 4 x - 24=0→→→[Breaking the middle term i.e term containing x]

⇒ x(x+6) -4(x+6)=0

⇒(x-4)(x+6)=0

⇒x-4=0 ∧ x+6=0

⇒x = 4     ∧    x= -6

Put x=4 in equation 2,

y + 4 ×4=5

y + 16=5

y = 5-16

y= -11

As one solution is (-6, 29), The other solution of the system of equation is (4, -11).