The diagram below shows tangents to a circle at B and D. Find x

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sidneylww

22.12.2020

Mathematics

I am assuming the expression is (2x-3)(x+5) or (2x-3)(x-5). I will teach you how to solve for both as I am not sure which one you are asking for. There are 4 steps to multiplying.

1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.

(2x*x)+(2x*5)+(-3*x)+(-3*5)=(2 $x^{2}$ )+(10x)+(-3x)+(-15)=2 $x^{2}$ +7x-15

(2x*x)+(2x*-5)+(-3*x)+(-3*-5)=(2 $x^{2}$ )+(-10x)+(-3x)+(15)=2 $x^{2}$ -13x+15

Your answer is 2 $x^{2}$ +7x-15 or 2 $x^{2}$ -13x+15. Does that answer your question?

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The diagram below shows tangents to a circle at B and D. Find x​