The distance between new york city, ny, and louisville, ky is 720 miles. one morning a train traveling 80 mph left from new york. two hours later a slower train, traveling at 60 mph, left louisville. how many hours will the slower train travel for before both trains will arrive at the same point?

2 hours

Step-by-step explanation:

Given : The distance between New York City, NY, and Louisville, KY is 720 miles. One morning a train traveling 80 mph left from New York. Two hours later a slower train, traveling at 60 mph, left Louisville.

To find : How many hours will the slower train travel for before both trains will arrive at the same point?

Solution : Let the distance covered by NY is x

and  let the distance covered by KY is y

Total distance covered is     ........[1]

→ New York city,

Distance traveled = x

Speed of the train = 80 mph

Time taken = t+2

Formula is

.......[2]

→ Louisville,

Distance traveled = y

Speed of the train = 60 mph

Time taken = t

Formula is

.......[3]

Put the value of t from [3] into [2]

 ......[4]

Now, we solve equation [1] and [4],

Put the value of y from [1] and put back in [4],

Put x=480 in [1]

So, The distance covered by train from New York city is x=480 miles

The distance covered by train from Louisville is y=240 miles.

Now put value of y in [3] to get time,

So, The time taken by train from Louisville is 4 hr.

The time taken by train from New York city is t+2=4+2=6 hr.

→ 6-4=2 hours will the slower train travel for before both trains will arrive at the same point.

The simplified expression would be 4

Step-by-step explanation:

So since we have parentheses in this expression we have to use the steps of PEMDAS (parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

So the first step is to solve what's in the parentheses

Then we multiply

Since we have simplified the equation so far let's write it out

Now we just solve the equation as written