The drama club is selling short-sleeved shirts for $5 Let x represent the number of short-sleeved shirts each, and long-sleeved shirts for $10 each. They hope to ordered and let y represent the number of long-sleeve
sell all of the shirts they ordered, to earn a total of
shirts ordered.
$1,750. After the first week of the fundraiser, they sold How many short-sleeved shirts were ordered?
3
of the short-sleeved shirts and 15 of the long-sleeved
How many long-sleeved shirts were ordered?
shirts, for a total of 100 shirts.
This system of equations models the situation.
5x + 10y = 1,750
**+ y = 100

This data is Inaccurate Data

            Equations of the system are When The situation is described is modeled by the following system of equations: Step first 5x + 10y = 1,750     Step second x + y = 100

   Where are  

x = number of short-sleeved shirts y = number of long-sleeved shirts

Divide first by 5:

Then third step will be  x + 2y = 350      

Multiplye secondly by -2:

-2x - 2y = -200

Add with the third one -x = 150 x = -150 Then, The value of x should not be negative.  also, This happens because the problem is inaccurately stated. Not even selling 100 of the $10 shirts we can get to $1,750. If the total shirts sold was 200, then it  secondly x + y = 200         And then x = 50, y=150 was an acceptable solution.

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Innacurate Data

Step-by-step explanation:

System of Equations

The situation described is modeled by the following system of equations:

5x + 10y = 1,750         [1]

x + y = 100         [2]

Where

x = number of short-sleeved shirts

y = number of long-sleeved shirts

Divide [1] by 5:

x + 2y = 350       [3]

Multiply [2] by -2:

-2x - 2y = -200

Add with [3]:

-x = 150

x = -150

The value of x should not be negative. This happens because the problem is inaccurately stated. Not even selling 100 of the $10 shirts we can get to $1,750.

If the total shirts sold was 200, then

x + y = 200         [2]

And x = 50, y=150 was an acceptable solution

Ais right because2(14)+2(11) is 28+22 which equals 50and2(14)-s which is saying 28-11 does equal 17