Mathematics: The driver of a car traveling at 42 ft/sec suddenly applies the brakes. The position of the car is s equals 42 t minus 3 t squared comma t seconds after the driver applies the brakes. How far does the car go before coming to a stop?

The driver of a car traveling at 42 ft/sec suddenly

mistydsargentp5wrh4

29.01.2022

after 7 seconds the driver applied the brakes to stop the car.

Step-by-step explanation:

Given:

The position of the car s(t)= 42t-3t^2

∴Speed of the car = $\frac{ds}{dt}=\frac{d(42t-3t^2)}{dt}=42-6t$

When car stopped the speed of car=0

$\Rightarrow42-6t=0\\\Rightarrow6t=42\\\Rightarrow\ t=7$

Therefore, after 7 seconds the driver applied the brakes to stop the car.

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groovyghoulie5630

29.04.2020

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