Mathematics: The end points of one diagonal of a rhombus are (-5,2) and (1,6). if the coordinates of the 3rd vertexare (-6,10), what are the coordinates of the 4th vertex? a.(2,-2) ,0) c.(4,8) d(-9,8)

The end points of one diagonal of a rhombus are

Ответ:

Solany6426

13.03.2022

Look at the picture.

$E\left(\dfrac{-5+1}{2};\ \dfrac{2+6}{2}\right)\to E\left(\dfrac{-4}{2};\ \dfrac{8}{2}\right)\to E(-2;\ 4)$

$\vec{BE}=[-2-(-6);\ 4-10]=[4;\ -6]$

$D(x;\ y)\\\\\vec{ED}=[x-(-2);\ y-4]=[x+2;\ y-4]\\\\\vec{ED}=\vec{BE}\ therefore\\\\ \ [x+2;\ y-4]=[4;\ -6]\to x+2=4\ and\ y-4=-6\\\\x=2\ and\ y=-2\\\\\ \boxed{A.\ (2;\ -2)}$
The end points of one diagonal of a rhombus are (-5,2) and (1,6). if the coordinates of the 3rd vert

The end points of one diagonal of a rhombus are (-5,2) and (1,6). if the coordinates of the 3rd vert

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Ответ:

jackchelly

16.08.2020

Mathematics

First things first. You need to know the formula for finding volume of a pyramid.

The formula is V=1/3Bh or Volume=1/3*Base Area*height

-Remember >Capital B means base area...not base

What did the problem give us?

-The height of the pyramid is 6 cm
-The length and width of the base is 2 cm

Lets plug what we know into the formula.

V=1/3Bh > 1/3(4)6
Now you would have to solve it.

1/3(4)=1.33333333333

1.33333333333*6=8

So the answer is 8 cm.

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The end points of one diagonal of a rhombus are (-5,2) and (1,6). if the coordinates of the 3rd vertexare (-6,10), what are the coordinates of the 4th vertex? a.(2,-2) ,0) c.(4,8) d(-9,8)

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