Mathematics: The engineer weighed two pieces of metal for an experiment. the piece of iron weighed 5 1⁄4 pounds and the piece of aluminum weighed 1 7⁄8 pounds. how much more did the piece of iron weigh than the piece of aluminum?

The engineer weighed two pieces of metal for

Ответ:

phillipmccormick

13.03.2022

Mathematics

Convert the mixed numbers into fractions.

$5 \frac{1}{4}$
5 * 4 = 20

$5 \frac{1}{4} = \frac{21}{4}$

$1 \frac{7}{8}$
1 * 8 = 8

$1 \frac{7}{8} = \frac{15}{8}$

Because both fractions have different denominators, we have to change one fraction so that its denominator will match. We will take 21/4 and multiply both the numerator and denominator by 2 so that it will match the denominator of 15/8:

$\frac{21}{4} * \frac{2}{2} = \frac{42}{8}$

Now we can subtract 42/8 by 15/8:

$\frac{42}{8} - \frac{15}{8} = \frac{27}{8}$

Convert the fraction back into a mixed number:

$27 / 8 = 3 R3 = 3 \frac{3}{8}$

The piece of iron weighted 3 and three-eighths pounds more than the piece of aluminum.

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The engineer weighed two pieces of metal for an experiment. the piece of iron weighed 5 1⁄4 pounds and the piece of aluminum weighed 1 7⁄8 pounds. how much more did the piece of iron weigh than the piece of aluminum?

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