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shay03littletop5kx2p
25.08.2019 •
Mathematics
The equation 3x + 6 = 12 involves two operations performed on x: multiplication by 3 followed by addition of 6. what operations were used to isolate x?
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Ответ:
First operation was subtraction (subtracting 6 to leave 3x alone)
Second operation was division (Dividing 3 from 3x to isolare x)
3x + 6 = 12
3x + 6 -(6) = 12 - 6
3x = 6
3 and 3 cancels out
x = 2
Ответ:
x = -1/3
Step-by-step explanation:
x = [-6 +- squareRoot(36-4x9)] / 2 times (-6)
= -6/18 = -1/3
x-(-1/3) = 0 ---> x = -1/3