Mathematics: The equation for a circle is x2−8x+y2−2y−8=0 . what is the equation of the circle in standard form?

The equation for a circle is x2−8x+y2−2y−8=0 . what

swaggaming941

02.01.2022

The equation of the given circle in standard form is:

(x-4)^2+(y-1)^2=5^2

Step-by-step explanation:

The standard form of a circle is given by the equation:

(x-h)^2+(y-k)^2=r^2

where (h,k) represent the center of the circle and r denotes the radius of the circle.

Hence, we are given equation as:

x^2-8x+y^2-2y-8=0

On solving as follows:

$x^2+(4)^2-8x+y^2+1^2-2y-(4)^2-1^2-8=0\\\\\\(x-4)^2+(y-1)^2-25=0\\\\\\(x-4)^2+(y-1)^2=25\\\\\\(x-4)^2+(y-1)^2=5^2$

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alissalhenry

15.08.2021

o-0

Explanation:

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